At a point on the surface of the earth, the value of the horizontal component of earth's magnetic field is equal to value of vertical magnetic component of earths magnetic field the angle of dip is

  • A

    $\frac {\pi }{4}$

  • B

    $\frac {\pi }{3}$

  • C

    $\frac {\pi }{6}$

  • D

    $\frac {\pi }{2}$

Similar Questions

Dip angle are $30^o$ and $45^o$ at two different places, then ratio of horizontal component of earth magnetic field at these place will be

The angle of dip at a place on the earth gives

The direction of the null points is on the equatorial line of a bar magnet, when the north pole of the magnet is pointing

Consider the plane $\mathrm{S}$ formed by the dipole axis and the axis of earth. Let $\mathrm{P}$ be point on the magnetic equator and in $\mathrm{S}$. Let $\mathrm{Q}$ be the point of intersection of the geographical and magnetic equators. Obtain the declination and dip angles at $\mathrm{P}$ and $\mathrm{Q}$

The magnetic needle of a tangent galvanometer is deflected at an angle $30^o$ due to a magnet. The horizontal component of earth’s magnetic field $0.34 \times {10^{ - 4}}\,T$ is along the plane of the coil. The magnetic intensity is

  • [AIIMS 2000]